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Total 40 documents matching your query.

1. Re: replace missing with previous value (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Wed, 01 Feb 2006 12:39:15 -0500
[1] "Johnson" "" "" "Johnson" "Smith" [6] "" "" "Smith" "Johnson" "Johnson" [11] "" "" "Smith" "Smith" "Johnson" [16] "Johnson" "" "" "Smith" "Johnson" [21] "Smith" "Johnson" "Smith" "" "Smith" [26]
/archives/html/s-news/2006-02/msg00003.html (12,150 bytes)

2. Re: extracting sample size per group (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Thu, 06 Oct 2005 14:09:40 -0400
table(tmod$groups$g) For example: 1 2 3 4 5 6 7 8 9 10 98 98 99 99 97 96 97 99 98 99 I am aware of how to extract the coefficients by group for a linear mixed effects model (e.g., coef (/lme.model/),
/archives/html/s-news/2005-10/msg00012.html (9,442 bytes)

3. Re: [Q]: R^2 in lm (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 10 Jun 2005 10:36:24 -0400
[1] 0.03490228 I have a very simple question on linear regression: does Splus function lm provide R^2? I checked help but could not find it. Of course one can always get it by using the residual to
/archives/html/s-news/2005-06/msg00034.html (8,682 bytes)

4. Re: SEs from lm (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 13 May 2005 07:46:09 -0400
h
/archives/html/s-news/2005-05/msg00085.html (9,271 bytes)

5. Re: Trellis plot in portrait page orientation (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Wed, 09 Mar 2005 11:35:51 -0500
Look at the help for trellis.device() and for the specific device you are using. For a graphsheet device, you might do this: trellis.device(graphsheet, orientation="portrait") xyplot(NOx ~ C | E, dat
/archives/html/s-news/2005-03/msg00040.html (8,568 bytes)

6. Re: Dates to Years (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 18 Mar 2005 02:51:57 -0500
How about coercing the result of years(x) to numeric? x <- dates(seq(0, 3660, 366)) as.numeric(as.character(years(x))) [1] 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 See ?years. hope this
/archives/html/s-news/2005-03/msg00089.html (9,844 bytes)

7. Re: Using seq function (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Tue, 29 Mar 2005 04:51:06 -0500
How about this: sort(c(seq(1,27,4), seq(2,28,4))) [1] 1 2 5 6 9 10 13 14 17 18 21 22 25 26 -- Chuck Cleland, Ph.D. NDRI, Inc. 71 West 23rd Street, 8th floor New York, NY 10010 tel: (212) 845-4495 (Tu
/archives/html/s-news/2005-03/msg00152.html (7,650 bytes)

8. Re: changing y label (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Sun, 06 Feb 2005 07:20:03 -0500
You might try something like this: x <- rnorm(20) y <- runif(20) par(las=1) plot(x, y, yaxt="n", ylim=c(0,1)) axis(side=2, at=seq(0,1,.1), labels=paste(seq(0,100,10), "%", sep="")) see ?axis hope thi
/archives/html/s-news/2005-02/msg00021.html (7,744 bytes)

9. Re: How to convert lower cases to UPPER CASES. (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 28 Jan 2005 09:46:28 -0500
x
/archives/html/s-news/2005-01/msg00150.html (8,333 bytes)

10. Re: Bar chart (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Tue, 19 Oct 2004 05:17:45 -0400
One bar for each row? Do you really want 132 bars per plot? How about something like this: mymat <- matrix(runif(132*6), ncol=6) par(las=1, mfrow=c(2,3)) for(i in 1:6){barplot(mymat[,i])} i have a ma
/archives/html/s-news/2004-10/msg00082.html (7,920 bytes)

11. Re: Joining of two data-frames with keyfields (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Tue, 07 Sep 2004 04:55:58 -0400
1
/archives/html/s-news/2004-09/msg00038.html (9,188 bytes)

12. Re: Delete a row with certain features (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Thu, 09 Sep 2004 07:31:20 -0400
l
/archives/html/s-news/2004-09/msg00050.html (9,091 bytes)

13. Re: aggregate (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 06 Aug 2004 04:58:59 -0400
mydata <- data.frame(V1 = c("A", "A", "A", "A", "B"), V2 = c("c", "d", "c", "c", "d"), INC = c(23, 67, 34, 23, 23), EXP = c(12, 32, 12, 1, 2)) aggregate(mydata[,c("INC", "EXP")], list(V1=mydata$V1, V
/archives/html/s-news/2004-08/msg00024.html (8,750 bytes)

14. Re: quick question:How to get two returns from a function (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 06 Aug 2004 05:49:49 -0400
As you have heard, you can put the results together in a list and then return the list. myfun <- function(){ A <- OLS(y ~ x1 + x2) B <- OLS(y ~ X3 + x4) ans <- list(A = A, B = B) return(ans) } fun<-f
/archives/html/s-news/2004-08/msg00026.html (8,640 bytes)

15. Re: Creating more than two level factor variables (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Tue, 31 Aug 2004 18:58:20 -0400
ary variabl
/archives/html/s-news/2004-08/msg00183.html (8,688 bytes)

16. Re: partial cor coeff (score: 1)
Author: Bartolomei" <surfprjab@hotmail.com>
Date: Fri, 11 Jun 2004 12:04:43 -0400
There was a thread on this in June of 2000. For example, http://tolstoy.newcastle.edu.au/R/help/00a/0515.html http://tolstoy.newcastle.edu.au/R/help/00a/0512.html You can search the archives here: ht
/archives/html/s-news/2004-06/msg00097.html (8,155 bytes)

17. Re: partial cor coeff (score: 1)
Author: ck Cleland <ccleland@optonline.net>
Date: Fri, 11 Jun 2004 12:07:48 -0400
Sorry for not noticing this was posted to s-news, not r-help! http://tolstoy.newcastle.edu.au/R/help/00a/0515.html http://tolstoy.newcastle.edu.au/R/help/00a/0512.html You can search the archives her
/archives/html/s-news/2004-06/msg00098.html (8,004 bytes)

18. Re: polr (score: 1)
Author: rian Ripley <ripley@stats.ox.ac.uk>
Date: Sat, 19 Jun 2004 06:03:58 -0400
From ?polr you find: "The response should be a factor (preferably an ordered factor), which will be interpreted as an ordinal response, with levels ordered as in the factor." See ?ordered for how to
/archives/html/s-news/2004-06/msg00121.html (8,291 bytes)

19. Re: clustered boxplots (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Fri, 14 May 2004 03:12:09 -0400
How about something like this? mydata <- data.frame(Y1 = rnorm(30), Y2 = rnorm(30), Y3 = rnorm(30), GROUP = rep(c("A", "B", "C"), c(10,10,10))) par(mfrow=c(1,3)) boxplot(split(mydata$Y1, mydata$GROU
/archives/html/s-news/2004-05/msg00072.html (8,254 bytes)

20. Re: merge of data frame (score: 1)
Author: Chuck Cleland <ccleland@optonline.net>
Date: Thu, 17 Jul 2003 04:52:41 -0400
Annaële: Notice the "all" argument in ?merge. You probably want the following: ID X1 X2 1 1 T F 2 2 F NA 3 3 F F 4 4 T T 5 5 T NA 6 6 F F 7 7 F NA 8 8 T NA 9 9 F NA 10 10 F NA hope this helps, Chuc
/archives/html/s-news/2003-07/msg00121.html (7,911 bytes)


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