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Total 19 documents matching your query.

1. Creating MS access file (score: 1)
Author: "Pravin Jadhav" <pravinj@gmail.com>
Date: Tue, 28 Mar 2006 15:42:43 -0500
a
/archives/html/s-news/2006-03/msg00083.html (7,121 bytes)

2. model.tables (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Wed, 18 Jan 2006 19:51:21 -0500
I am conducting a simple univariate analysis of a repeated measures design. Where the response for each subject is measured at 3 visits. Here is a simplified version of the data and the model. The re
/archives/html/s-news/2006-01/msg00060.html (9,490 bytes)

3. Re: model.tables (Revised) (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Thu, 19 Jan 2006 16:11:53 -0500
Hello again, I have been told that the code did not work. Thanks! Here is a revised version. Revised: I am conducting a simple univariate analysis of a repeated measures design. Where the response fo
/archives/html/s-news/2006-01/msg00062.html (9,803 bytes)

4. Re: Alternative to model.tables.aov? (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Thu, 26 Jan 2006 13:39:14 -0500
I had similar problem last week with model.tables and I learned that the problem is a result of the line of code 'oldClass(ctable) <- "table"' in print.tables.aov(): .. names(dimnames(ctable)) <- na
/archives/html/s-news/2006-01/msg00091.html (10,435 bytes)

5. Re: Alternative to model.tables.aov? (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Sun, 29 Jan 2006 23:00:52 -0500
In fact, I tried se.contrast as well. Unfortunately, I could not get it work. A friend suggested using the lme procedure instead of aov procedure and helped me to set up the mixed model to obtain si
/archives/html/s-news/2006-01/msg00098.html (12,322 bytes)

6. NA's in LME (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Wed, 14 Dec 2005 11:25:56 -0500
In LME, the default action for the missing data is 'na.fail'. My aim is to obtain predictions for the missing data based on individual random effects. One option would be to get the output and do th
/archives/html/s-news/2005-12/msg00042.html (6,876 bytes)

7. passing arguments to a function (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Mon, 19 Dec 2005 15:24:37 -0500
Dear all, For my previous query (obtain predictions for the missing records), Dr. Pinheiro pointed me to the "predict" function. Thanks! It is doing exactly what I needed. But I am having some troubl
/archives/html/s-news/2005-12/msg00063.html (11,029 bytes)

8. Re: passing arguments to a function (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Mon, 19 Dec 2005 16:59:18 -0500
Hi again, I have made it work with a very straightforward modification (rather ugly one). Please ignore the previous message unless you have a better solution for me. fit.F<-function (data, byvar, fu
/archives/html/s-news/2005-12/msg00065.html (12,925 bytes)

9. key (score: 1)
Author: u.tw>
Date: Fri, 1 Apr 2005 15:12:10 -0500
Dear all, A quick question about ?key. I have the following statement in my code. key( corner=c(1,1), text=c("1st option", "2nd option"), rectangle=list(size=5, angle=c(-45,45), density=10) ) I would
/archives/html/s-news/2005-04/msg00003.html (7,052 bytes)

10. Re: Exporting to Excel spreadsheet with multiple worksheets (score: 1)
Author: .gov>
Date: Wed, 13 Apr 2005 21:52:47 -0400
cify the workshee
/archives/html/s-news/2005-04/msg00090.html (15,291 bytes)

11. Re: loop over a series regression models (score: 1)
Author: .edu>
Date: Fri, 15 Apr 2005 11:42:31 -0400
2024 0.9910637 y2
/archives/html/s-news/2005-04/msg00116.html (16,738 bytes)

12. bootstrap (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Mon, 28 Mar 2005 22:05:04 -0500
Hello all, I am kind of stuck with this problem. Any help is appreciated. Say, I have a following dataset(illustration purposes): ID TIME OBS 1 1 11 1 2 8 1 3 5 2 1 7 2 2 11 2 3 9 3 1 10 3 2 10 3 3 1
/archives/html/s-news/2005-03/msg00150.html (7,668 bytes)

13. function (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Thu, 17 Feb 2005 17:23:06 -0500
I am writing a small function to fit an LME model. fit.data<-function(data) { lme.fit<-by(data, data$rep, function (x) lme(resp~time, data=x, random=list(id=pdDiag(~1+time)))) return(lme.fit) } It W
/archives/html/s-news/2005-02/msg00097.html (8,078 bytes)

14. help with a function (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Thu, 17 Feb 2005 17:19:37 -0500
I am writing a a small function to fit an LME model. fit.data<-function(data) { lme.fit<-by(data, data$rep, function (x) lme(resp~time, data=x, random=list(id=pdDiag(~1+time)))) return(lme.fit) } It
/archives/html/s-news/2005-02/msg00099.html (8,171 bytes)

15. Re: function (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Sat, 19 Feb 2005 19:36:09 -0500
Thanks to Patrick. I was able to include formula as one of the arguments and pass to the inner function. Somehow it was not working before I posted previous message. S poetry was really useful. Thank
/archives/html/s-news/2005-02/msg00106.html (10,443 bytes)

16. Importing a lot of Excel Worksheets into a data frame (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Thu, 2 Dec 2004 15:11:32 -0500
I have slightly problematic dataset where data are stored in one EXCEL file but several different worksheets. The format of all worksheets is the same. The 'import' function reads only the first wor
/archives/html/s-news/2004-12/msg00011.html (7,851 bytes)

17. Re: parameter constraints in nlme? (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Sun, 5 Dec 2004 14:23:03 -0500
Hi Ronald, For a different problem, we were looking for a similar feature in NLME. As it turns out, there is no straightforward solution. I doubt if one can constrain parameters in NLME implemented i
/archives/html/s-news/2004-12/msg00023.html (13,782 bytes)

18. first record per occasion (score: 1)
Author: Pravin Jadhav <pravinj@gmail.com>
Date: Sun, 28 Nov 2004 23:08:28 -0500
-news-owner
/archives/html/s-news/2004-11/msg00157.html (8,505 bytes)

19. pattern (score: 1)
Author: "Pravin Jadhav" <pravinj@gmail.com>
Date: Tue, 16 May 2006 11:47:59 -0400
I have the following vector I am interested in knowing the number of letters in each character string. The output should be (2, 3, 3). I can do this when there is no "+" sign in between [1] 2 3 3 I
/archives/html/s-news/2006-05/msg00052.html (7,566 bytes)

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