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Total 14 documents matching your query.

1. Data manipulation (score: 1): Author: GRAHAM LEASK <grahamleask@btopenworld.com>; Date: Sun, 23 Apr 2006 14:40:48 +0100 (BST); esu; /archives/html/s-news/2006-04/msg00105.html (7,495 bytes)
2. Re: Data manipulation (score: 1): Author: "Dimitrios Chalvatzis" <dimitrios.stats@btopenworld.com>; Date: Sun, 23 Apr 2006 16:53:53 +0100; t N; /archives/html/s-news/2006-04/msg00106.html (11,479 bytes)
3. Re: Data manipulation (score: 1): Author: "Dimitrios Chalvatzis" <dimitrios.stats@btopenworld.com>; Date: Sun, 23 Apr 2006 16:57:21 +0100; Fr; /archives/html/s-news/2006-04/msg00107.html (13,357 bytes)
4. Data Manipulation (score: 1): Author: "Overstreet, Jason (FL51)" <Jason.Overstreet@honeywell.com>; Date: Tue, 10 Jan 2006 08:35:44 -0700; One day, I will be answering questions on this list instead of asking. In the mean time, I have another data manipulation question. Below is an example of data having a variable of interest (V1) with; /archives/html/s-news/2006-01/msg00027.html (12,214 bytes)
5. Re: Data Manipulation (score: 1): Author: "Overstreet, Jason (FL51)" <Jason.Overstreet@honeywell.com>; Date: Tue, 10 Jan 2006 09:01:19 -0700; Slight correction...I forgot that V4 is what I want to use as the group variable. JLO One day, I will be answering questions on this list instead of asking. In the mean time, I have another data mani; /archives/html/s-news/2006-01/msg00028.html (12,380 bytes)
6. Re: Data Manipulation (score: 1): Author: "Richard M. Heiberger" <rmh@temple.edu>; Date: Tue, 10 Jan 2006 11:55:58 -0500; I think you want tapply + d=factor(c(1,2,1,2,2,1))) a b d 1 1 a 1 2 2 a 2 3 3 b 1 4 1 b 2 5 1 b 2 6 2 c 1 1 2 a 1 2 b 3 1 c 2 NA This says that the average of the b="a" and d=1 cells is 1. etc; /archives/html/s-news/2006-01/msg00029.html (6,889 bytes)
7. Data manipulation (score: 1): Author: "Scott Rollins" <rollins8@msu.edu>; Date: Wed, 19 Jun 2002 10:42:26 -0400; I'm in need of data manipulation help. This is the first time I've tried to use S-Plus (version 4.5 running in Windows ME) for cluster analysis. I have a dataframe containing 3 columns: site, species; /archives/html/s-news/2002-06/msg00169.html (7,595 bytes)
8. Re: Data manipulation (score: 1): Author: "Gunter, Bert" <bert_gunter@merck.com>; Date: Wed, 19 Jun 2002 21:05:48 -0400; 1. Read the Help manuals. Why is this not the first place that you look? 2. Eventually, if you need to use the software a lot and want to do it well, get a copy of S-PROGRAMMING by Venables and Riple; /archives/html/s-news/2002-06/msg00170.html (9,513 bytes)
9. Re: Data manipulation (score: 1): Author: Don MacQueen <macq@llnl.gov>; Date: Thu, 20 Jun 2002 08:00:20 -0700; Why don't you give a short example of the data manipulation you need to perform. That is, a few rows of a data frame and the matrix it would become. You mention a "crosstab" query. So try help(crosst; /archives/html/s-news/2002-06/msg00177.html (9,051 bytes)
10. Re: Data manipulation (score: 1): Author: "David L Lorenz" <lorenz@usgs.gov>; Date: Fri, 21 Jun 2002 07:35:56 -0500; The function tapply will do what you want. Try this: out.mat <- tapply(df[["ra"]], df[c("site","species")], FUN=sum) You will need to replace the NAs in out.mat with 0s. What kind of distance functi; /archives/html/s-news/2002-06/msg00188.html (11,116 bytes)
11. Re: Data manipulation (score: 1): Author: Renaud Lancelot <lancelot@sentoo.sn>; Date: Thu, 20 Jun 2002 08:43:54 +0000; Here is an example of what you can do, adapted from function cass.ind found inside function mca in package MASS: cass.ind <- function(cl) { n <- length(cl) cl <- as.factor(cl) x <- matrix(0, n, lengt; /archives/html/s-news/2002-06/msg00195.html (10,424 bytes)
12. Data manipulation (score: 1): Author: "Khan, Sohail" <khan@cshl.edu>; Date: Wed, 27 Sep 2006 15:20:36 -0400; Dear list, I have a data frame as: id ratio abs.pos a 1.5 25 b 2.5 36 c 1.9 48 d 2.3 57 e 2.9 66 f 1.3 74 I would like to do something like: abs.pos1 + 10 = x while x < abs.pos2.....abs.pos3.....abs.; /archives/html/s-news/2006-09/msg00062.html (6,335 bytes)
13. data manipulation (score: 1): Author: "Zheng_Jenny" <Zheng_Jenny@Allergan.com>; Date: Fri, 27 Oct 2006 11:33:40 -0700; Would anyone help me with the problem below? I have a dataset x including ID, Time, DV and ID2. I can use x$DV[x$Time==0]_0 to make DV=0 when Time is 0 but when I was trying to use command “x$; /archives/html/s-news/2006-10/msg00062.html (11,607 bytes)
14. Re: data manipulation (score: 1): Author: David L Lorenz <lorenz@usgs.gov>; Date: Fri, 27 Oct 2006 13:58:26 -0500; You are getting the error because ID2 is a factor and there is no level "zero." You have 2 choices: 1 redo the ID2 column and add a level "zero" or convert ID2 to character. Note that you can preven; /archives/html/s-news/2006-10/msg00063.html (10,304 bytes)

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