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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*Matrix\s+row\s+multiplication\s+with\s+a\s+quick\s+dos\.time\?\s*$/: 3 ]

Total 3 documents matching your query.

1. Matrix row multiplication with a quick dos.time? (score: 1): Author: Adam Brentnall <a.r.brentnall@maths.soton.ac.uk>; Date: Wed, 25 Feb 2004 16:13:12 +0000; Dear users of S-news As part of a function I would like to calculate transpose(A) %*% A so that the first row of transpose(A) is matched with the 1st row of A. The second row of Transpose(A) is match; /archives/html/s-news/2004-02/msg00211.html (8,318 bytes)
2. Re: Matrix row multiplication with a quick dos.time? (score: 1): Author: Sundar Dorai-Raj <sundar.dorai-raj@PDF.COM>; Date: Wed, 25 Feb 2004 10:28:47 -0600; Try crossprod(A) instead. [1] 5.187 [1] 4.958 [1] 1.071 [1] 0.721 [1] T Regards, Sundar Adam Brentnall wrote: Dear users of S-news As part of a function I would like to calculate transpose(A) %*% A s; /archives/html/s-news/2004-02/msg00213.html (10,213 bytes)
3. Re: Matrix row multiplication with a quick dos.time? (score: 1): Author: Prof Brian Ripley <ripley@stats.ox.ac.uk>; Date: Wed, 25 Feb 2004 16:56:57 +0000 (GMT); That was my idea, but that seems not to be what he actually wants but rather diag(diag(crossprod(t(A)))) given the numerical example. I think we need to know if it is A or t(A), if A is 18 x 900. If; /archives/html/s-news/2004-02/msg00214.html (10,866 bytes)

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