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1. This must be a simple task... (score: 1): Author: "Kim Elmore" <Kim.Elmore@noaa.gov>; Date: Fri, 22 Jul 2005 17:21:31 -0500; I have a data frame (several, really) that have a structure I'm trying to unravel. After column 1, which contains duplicates, each succeeding column contains new data *plus* all the data form column; /archives/html/s-news/2005-07/msg00120.html (8,771 bytes)
2. Re: This must be a simple task... (score: 1): Author: "Kim Elmore" <Kim.Elmore@noaa.gov>; Date: Fri, 22 Jul 2005 21:49:41 -0500; I apologize for not being more clear; I admit being in a hurry to get the kids from day care. Regardless, I don't mean for the group to divine my problem based on my poor description: yes, these data; /archives/html/s-news/2005-07/msg00121.html (10,986 bytes)
3. Re: This must be a simple task... (score: 1): Author: "Kim Elmore" <Kim.Elmore@noaa.gov>; Date: Fri, 22 Jul 2005 22:38:36 -0500; The functions provided by Sam Buttrey and Tom Jagger both do exactly what I need to do, and both use parts of S about which I was ignorant. I am now slightly less ignorant and thank both of you for r; /archives/html/s-news/2005-07/msg00122.html (7,765 bytes)
4. Re: This must be a simple task... (score: 1): Author: "Thomas Jagger" <tjagger@blarg.net>; Date: Sat, 23 Jul 2005 10:19:36 -0600; Hi, maybe I am missing something here. Columns in a data frame all have the same length, so what are you replacing the say three values of 1.5 with? If you mean that you have a list and order is not; /archives/html/s-news/2005-07/msg00123.html (10,760 bytes)

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