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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*lapply\s+question\s*$/: 6 ]

Total 6 documents matching your query.

1. lapply question (score: 1)
Author: Eric yang <yang_eric9@yahoo.com>
Date: Tue, 30 Aug 2005 09:11:19 -0700 (PDT)
s
/archives/html/s-news/2005-08/msg00134.html (9,466 bytes)

2. Fwd: lapply question (score: 1)
Author: "Richard M. Heiberger" <rmh@temple.edu>
Date: Tue, 30 Aug 2005 12:28:54 -0400
i
/archives/html/s-news/2005-08/msg00135.html (8,361 bytes)

3. lapply question (score: 1)
Author: Dave Evens <devens8765@yahoo.com>
Date: Tue, 19 Jul 2005 06:35:26 -0700 (PDT)
Dear members, I have numerous arrays that are organised in a list. For example, suppose I have 2 arrays in a list called alist alist <- list(array(rpois(12,5), 6:8) , array(rpois(15,5), 10:12)) with
/archives/html/s-news/2005-07/msg00108.html (8,472 bytes)

4. Re: lapply question (score: 1)
Author: Patrick Burns <pburns@pburns.seanet.com>
Date: Tue, 19 Jul 2005 14:56:11 +0100
Your problem with 'names' is that you are using a list where you should use a vector. That is: names(alist) <- c('array 1', 'array 2') On the 'lapply' question, you should be able to do it, I would w
/archives/html/s-news/2005-07/msg00109.html (10,049 bytes)

5. lapply question (score: 1)
Author: Mike Kattan <Mike@kattan.net>
Date: Sat, 6 Jan 2001 12:23:59 -0500
I have a dataframe "m" which I'd like to rescale based on another dataframe. I'm led to believe "lapply" might be the most efficient way to accomplish this. For example, the following code rescales b
/archives/html/s-news/2001-01/msg00027.html (7,454 bytes)

6. RE: lapply question (score: 1)
Author: Mike Kattan <Mike@kattan.net>
Date: Sat, 6 Jan 2001 17:08:29 -0500
In nanoseconds, Tim Hesterberg and Bill Dunlap responded with solutions. Both included possibilities along the lines of the following: (for j in names(x)) { xj _ x[[j]] if(xj is numeric){ rescale usi
/archives/html/s-news/2001-01/msg00029.html (7,770 bytes)

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