Mail Archive Search: <+subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*object\.size\s*$/>

Results:

References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*object\.size\s*$/: 2 ]

Total 2 documents matching your query.

1. object.size (score: 1): Author: Jewel Bright <jwlbright@yahoo.com>; Date: Tue, 26 Jul 2005 05:05:09 -0700 (PDT); dear friends: i need to evaluate and sort the size of all the objects in my working frame. i tried object.size(objects()) and lapply(X=objects(), FUN=object.size) they produce some kind of numbers wh; /archives/html/s-news/2005-07/msg00139.html (7,271 bytes)
2. Re: object.size (score: 1): Author: "Alan Hochberg" <alan.hochberg@prosanos.com>; Date: Tue, 26 Jul 2005 14:18:05 -0400; I think that the function you gave ends up looking at object sizes for character vectors representing the names of your objects, or some such funky S-like thing. This seems to work:<o:p></o:p> <o:p>; /archives/html/s-news/2005-07/msg00140.html (11,076 bytes)

Current List: 1 - 2
Page: [1]