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1. predict rpart (score: 1): Author: nj7w@virginia.edu; Date: Thu, 20 Jun 2002 09:26:29 -0400 (EDT); Is there any function similar to predict.tree in rpart? I have got the model from rpart, and now I wish to predict the classes of different samples using the result of training data. Thanks. Nitin -; /archives/html/s-news/2002-06/msg00173.html (6,907 bytes)
2. Re: predict rpart (score: 1): Author: Prof Brian D Ripley <ripley@stats.ox.ac.uk>; Date: Thu, 20 Jun 2002 14:53:26 +0100 (GMT Daylight Time); See the worked examples in Venables & Ripley. -- Brian D. Ripley, ripley@stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861; /archives/html/s-news/2002-06/msg00174.html (7,990 bytes)
3. Re: predict rpart (score: 1): Author: "Marion Verduijn" <m.verduijn@amc.uva.nl>; Date: Thu, 20 Jun 2002 15:58:53 +0200; predict.rpart(name of rpart model, newdata=...) is a function similar to predict.tree. Regards, Marion Verduijn University of Amsterdam. --Original Message-- From: s-news-owner@lists.biostat.wustl.e; /archives/html/s-news/2002-06/msg00175.html (7,813 bytes)

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