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Re: Simple Variance Component Analysis

To: "'jmp-l@lists.biostat.wustl.edu'" <jmp-l@lists.biostat.wustl.edu>
Subject: Re: Simple Variance Component Analysis
From: "Schnelle, Karl" <kschnelle@dow.com>
Date: Wed, 31 Aug 2005 07:47:36 -0400
Instead of selecting Fit Model, one may also use Graph - Variability/Gage 
Chart.  Select your X and Y and then under Variability Gage, select Variance 
Component.

The advantages are that you get the REML method and you get the Variability 
Chart (which helps you visualize the within lot versus the between lot 
variability).  See the .jrn file.

Karl
_________________________________________________


-----Original Message-----
From: jmp-l-owner@lists.biostat.wustl.edu 
[mailto:jmp-l-owner@lists.biostat.wustl.edu] On Behalf Of 
Gunter.Hartel@csl.com.au
Sent: Tuesday, August 30, 2005 6:31 PM
To: jmp-l@lists.biostat.wustl.edu
Subject: Re: [jmp-l] Simple Variance Component Analysis


Dear Sean,
That can happen sometimes when the within lot variance is actually larger than 
the between lot variance.  For example in biometrics you can have a within plot 
negative correlation arising from a competitive situation where one plant being 
larger makes the other plant in that plot smaller.  

Looking at your data you have a situation where in some lots the difference is 
extremely small, eg sd<10, and in some lots it is quite large, eg sd>300.  You 
might see if there is an explanation for that. 
Cheers
Gunter


                -----Original Message-----
                From:   jmp-l-owner@lists.biostat.wustl.edu 
[mailto:jmp-l-owner@lists.biostat.wustl.edu] On Behalf Of Davern, Sean
                Sent:   Wednesday, 31 August 2005 6:13 AM
                To:     'jmp-l@lists.biostat.wustl.edu'
                Subject:        Re: [jmp-l] Simple Variance Component Analysis

                So what does it mean when the Lot&Random component of variance 
is -22% of
                the total? 
                How is it possible for the Var Comp Est to be negative?

                Sean

                -----Original Message-----
                From: jmp-l-owner@lists.biostat.wustl.edu
                [mailto:jmp-l-owner@lists.biostat.wustl.edu]On Behalf Of
                Martin_Kane@hgsi.com
                Sent: Tuesday, August 30, 2005 12:51 PM
                To: jmp-l@lists.biostat.wustl.edu
                Subject: Re: [jmp-l] Simple Variance Component Analysis



                The correct way to do this analysis is to use the "Fit Model" 
analysis.
                Put "Response" in the Y role and put "Lot" in the Effects role. 
 Now,
                highlight "Lot" in the effects box and select the red 
"Attributes" arrow.
                With this "Attributes" menu, select "Random Effect".  This will 
change the
                effect from "Lot" to "Lot& Random".

                Doing this will allow you to get variance components out.

                Unfortunately, your data set seems to have much more 
variability within lot
                than lot-to-lot.

                Sincerely,

                Martin Kane
                Manager, Non-Clinical Statistics
                Human Genome Sciences, Inc.
                240-314-4400 x3822


                 

                                      "Davern, Sean"

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                Simple Variance Component Analysis                       
                 

                 

                                      08/30/2005 03:42 PM

                                      Please respond to jmp-l

                 

                 





                Can anyone tell me how to get JMP to give a very simply 
variance component
                analysis?

                I'm trying to quantify lot-to-lot variability of a raw 
material.  I've made
                two independent measurements of 9 lots.  I'd like to segregate 
the overall
                variance into within lot variation (coming from run-to-run 
variation) and
                between lot (lot-to-lot) variation.  I'd like the total 
variance to be
                reported as the two components.
                   Attached is the example data set.
                 <<Example Data.JMP>>
                   It seems like this should be very simple but I can't seem to 
get the
                answer without doing the calculations by hand.
                Thanks,
                Sean

                Sean Davern
                Engineer III
                Cell Sciences Process Development
                Mail Stop AW2/D2152
                Ext. 57074

                (See attached file: Example Data.JMP)

                

Attachment: example data1.JRN
Description: Binary data

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