Very instructive, and thank you for mentioning it. But I haven't finished
learning yet...
> foo <- list(z=1:4, b=9:7, x=runif(3))
> do.call('c',foo)
z1 z2 z3 z4 b1 b2 b3 x1 x2 x3
1 2 3 4 9 8 7 0.5649553 0.4697681 0.48498
> do.call('min',foo)
[1] 0.4697681
> do.call('max',foo)
[1] 9
> do.call('range',foo)
[1] 0.4697681 9.0000000
> do.call('mean',foo)
Error in call to mean(): Argument z= not matched
Error in call to mean(): Argument b= not matched
Dumped
> mean(unlist(foo))
[1] 3.55197
>
-Don
At 3:09 PM -0800 5/19/98, Bill Venables wrote:
>Alan Donald writes:
> > This is rather a simple question that I remember running into
> > about a year ago and solving -- but I cannot remember how I
> > did it.
> >
> > I have a list whose components are numeric vectors of various
> > lengths. What I want to do is to strip the "list" structure
> > from the object so that I get a vector consisting of all the
> > components glued together. This is part of a program, so I
> > could -- I guess -- write a little program that trudges its
> > way through the list tacking vectors on to the end of a long
> > train of numbers. But I think there is a function in Splus
> > that will do this for me quickly. Searches through the Splus
> > 3.3 and 4 help files and manuals have turned up nothing. Must
> > be looking under the wrong word.
>
>The "I could kick myself" answer is, of course,
>
>> one.big.vector <- unlist(list.of.vectors).
>
>It then occurred to me that there is another answer almost as
>simple and somewhat more instructive:
>
>> one.big.vector <- do.call("c", list.of.vectors)
>
>Bill
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--------------------------------
Don MacQueen
Environmental Protection Dept.
Lawrence Livermore National Lab
macq@llnl.gov (925) 423-1062
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