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Re: [S] is there a cumouter() like function?

To: Jack Lewis <jlewis@imtsun.rsl.psw.fs.fed.us>
Subject: Re: [S] is there a cumouter() like function?
From: Claude Nadeau <nadeauc@CIRANO.UMontreal.CA>
Date: Tue, 25 Aug 1998 07:51:36 -0400 (EDT)
Cc: Fei Chen <fchen@stern.nyu.edu>, s-news@wubios.wustl.edu
In-reply-to: <35E1F572.2711D787@rsl.psw.fs.fed.us>
Sender: owner-s-news@wubios.wustl.edu
On Mon, 24 Aug 1998, Jack Lewis wrote:

> Oops, what I meant in the example below was:
> Given a sequence a[i], i=0,1,2,...,n, and some constant k,
> with 0 < k < 1, compute the sequence
> b[i] = k*b[i-1] + a[i],        i=1,2,...,n
> NOT
> b[i]= k*a[i-1]+a[i]
> Sorry, Jack
> P.S. I know it can be done with apply()
> 

How about filter(a,k,"rec") ?

Cheers,

Claude Nadeau

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