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Hi!
>dd1<-seq(from=1, by=1, length=5)
>comb <- expand.grid(x1 =dd1 , x2 =dd1, x3 =dd1, x4 = dd1, x5=dd1,
>xx6=dd1)
>This program gives you all combinations of c(1,2,3,4,5).
>If you replace "1" by "a", "2" by "b",-----, "5" by "e",
>it results in all combinations of a,b,c,d,e.
Program like below may be simpler; you do not have
to replace numbers by letters :
function()
{
dd1 <- c("a", "b")
comb <- expand.grid(x1 = dd1, x2 = dd1, x3 = dd1)
print(comb)
}
Result is :
x1 x2 x3
1 a a a
2 b a a
3 a b a
4 b b a
5 a a b
6 b a b
7 a b b
8 b b b
K. Takezawa
***** Kunio Takezawa, Ph.D. (takezawa@affrc.go.jp) *****
***** Research Information Section *****
**** Hokuriku National Agricultural Experiment Station, JAPAN ****
***** <http://www.inada.affrc.go.jp/~takezawa/patent-e.html> *****
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