| To: | <chris1@psyctc.org> |
|---|---|
| Subject: | Re: extracting a matrix from a data frame |
| From: | Tim Hesterberg x319 <timh@insightful.com> |
| Date: | Sun, 25 Mar 2001 14:47:09 -0800 |
| Cc: | s-news@lists.biostat.wustl.edu |
| In-reply-to: | <3ABCF4AC.23714.C2BB049@localhost> (chris1@psyctc.org) |
| References: | <3ABCF4AC.23714.C2BB049@localhost> |
| Reply-to: | timh@insightful.com (Tim Hesterberg) |
The question was how to convert some columns in a data frame into
an ordinary matrix.
Use e.g.
numerical.matrix(df[,3:6])
numerical.matrix(df[3:6]) # faster, but differs for data.frame & matrix
as.matrix(df[3:6])
data.matrix(df[3:6])
The three functions differ in how they handle non-numerical
variables like factors. Here are examples:
temp _ data.frame(a=1:2, b=letters[1:2], c=c(T,F))
S4> numerical.matrix(temp)
a b c
1 1 NA 1
2 2 NA 0
S4> numerical.matrix(temp, remove=T)
a c
1 1 1
2 2 0
S4> as.matrix(temp)
a b c
1 "1" "a" "T"
2 "2" "b" "F"
S4> data.matrix(temp)
a b c
1 1 1 1
2 2 2 0
attr(, "column.levels"):
$a:
NULL
$b:
[1] "a" "b"
$c:
NULL
Tim Hesterberg
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