| To: | <s-news@lists.biostat.wustl.edu> |
|---|---|
| Subject: | A problem in plot(x,y) |
| From: | "Dr.Takashi Kikuchi" <takashi.kikuchi@st-hughs.oxford.ac.uk> |
| Date: | Mon, 20 Jan 2003 11:35:05 -0000 |
| Organization: | University of Oxford |
|
Dear S-Plus user I experience en error message of "Error in plot.xy("plot"): Cannot find x and y in list" by a following codes. It may be a simple problem but I can not find the cause. I make a matrix with two columns corresponding to X and Y components and then extract each component to give it in a plot( X, Y) command. I think it must properly work. Please suggest the cause of the error. I use Windows2000 and S-Plus 2000 professonal version. Best regrads, Takashi Kikuchi University of Oxford %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% # Making a sequence n.sub_ seq(from=10, to=200, by=10) # Definition of a function l.ratio_ function(n.sub){ # constants Mk_5*10^6 M1_Mk*0.57 M2_Mk*0.29 M3_Mk*0.10 c_ 4*10^3 l.mean1_ -1.833 l.sd1_ 0.4469 l.mean2_ -1.505 l.sd2_ 0.4635 l.mean3_ -0.1564 l.sd3_ 0.6959 # core expressions l.smlt1_ rnorm(n.dat, mean=l.mean1, sd=l.sd1) ub.var1_ var(l.smlt1) rt1_ (1.63-mean(l.smlt1))/sqrt(ub.var1*(n.sub-1)) bft1_ M1/(1+exp(rt1)) l.smlt2_ rnorm(n.dat, mean=l.mean2, sd=l.sd2) ub.var2_ var(l.smlt2) rt2_ (1.63-mean(l.smlt2))/sqrt(ub.var2*(n.sub-1)) bft2_ M1/(1+exp(rt2)) l.smlt3_ rnorm(n.dat, mean=l.mean3, sd=l.sd3) ub.var3_ var(l.smlt3) rt3_ (1.63-mean(l.smlt3))/sqrt(ub.var3*(n.sub-1)) bft3_ M1/(1+exp(rt3)) # Output t.bft_bft1+bft2+bft3-c*n.sub return(t.bft)}
# Calculation of the function ans_ lapply(n.dat, l.ratio)
# Making a matrix for x-y plot n.subm_ as.matrix(n.sub) ansm_ as.matrix(ans) btdat_cbind(n.subm, ansm) btdat # Plotting plot(btdat[,1], btdat[,2]) |
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