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Re:

To: zahra ghenima <zhkfr@yahoo.fr>
Subject: Re:
From: Spencer Graves <spencer.graves@pdf.com>
Date: Tue, 23 Mar 2004 08:25:15 -0800
Cc: s-news@lists.biostat.wustl.edu
In-reply-to: <20040323142148.85063.qmail@web13503.mail.yahoo.com>
References: <20040323142148.85063.qmail@web13503.mail.yahoo.com>
User-agent: Mozilla/5.0 (Windows; U; Windows NT 5.0; en-US; rv:1.4) Gecko/20030624 Netscape/7.1 (ax)
> x <- 1:11
> y <- sin(x)
> fit3 <- lm(y ~ x + x^2 + x^3)
> summary(fit3)

Call: lm(formula = y ~ x + x^2 + x^3)
Residuals:
    Min      1Q  Median     3Q    Max
-0.6674 -0.3767 0.03571 0.4061 0.6786

Coefficients:
             Value Std. Error t value Pr(>|t|)
(Intercept)  3.0812  0.9753     3.1594  0.0159
         x -2.1496  0.6731    -3.1937  0.0152
    I(x^2)  0.4070  0.1275     3.1918  0.0152
    I(x^3) -0.0224  0.0070    -3.1958  0.0152

Residual standard error: 0.5507 on 7 degrees of freedom
Multiple R-Squared: 0.6454
F-statistic: 4.246 on 3 and 7 degrees of freedom, the p-value is 0.05257

Correlation of Coefficients:
      (Intercept)       x  I(x^2)
x -0.9298 I(x^2) 0.8498 -0.9781 I(x^3) -0.7845 0.9389 -0.9891
> coef(fit3)
(Intercept)         x    I(x^2)      I(x^3)
   3.081168 -2.149645 0.4069789 -0.02239129

Is this what you want? spencer graves

zahra ghenima wrote:

Hello
I have a function that I must codify with S-plus. In the function I have to determine the coefficients of the polynomial : (1+x+x^2+...+x^m)^n, with x is any variable and m, n take any natural value. How, we can define a polynomial, develop the polynomial

and extract the coefficients of the polynomial developped with Splus.
I wait from you an answer as soon as possible
thank you
Yours faithfully

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