| To: | Tim Wade <wade_tj@yahoo.com> |
|---|---|
| Subject: | Re: running sum of counts |
| From: | Sundar Dorai-Raj <sundar.dorai-raj@PDF.COM> |
| Date: | Mon, 19 Apr 2004 13:46:38 -0500 |
| Cc: | s-news@lists.biostat.wustl.edu |
| In-reply-to: | <20040419181637.93727.qmail@web12307.mail.yahoo.com> |
| Organization: | PDF Solutions, Inc. |
| References: | <20040419181637.93727.qmail@web12307.mail.yahoo.com> |
| Reply-to: | sundar.dorai-raj@PDF.COM |
| User-agent: | Mozilla/5.0 (Windows; U; Windows NT 5.0; en-US; rv:1.4) Gecko/20030624 Netscape/7.1 (ax) |
Tim Wade wrote: Hello: I have what I'm sure is a very simple question. I have a vector like this: 1 1 1 1 2 2 2 3 3 4 4 4 4 4 5 5 5 5 5 6 7 3 3 3 2 2. I would like to generate a sequence consisting of a running sum of count values, like this: 1 2 3 4 1 2 3 1 2 1 2 3 4 5 1 2 3 4 5 1 1 1 2 3 1 1. Thanks very much for any assistance! Tim Hi Tim,I'm assuming the last number in the second sequence should really be a 2 and not a one. My solution isn't pretty, but it does the job: > x [1] 1 1 1 1 2 2 2 3 3 4 4 4 4 4 5 5 5 5 5 6 7 3 3 3 2 2 > unlist(sapply(diff(c(0, which(diff(c(x, Inf)) != 0))), seq)) [1] 1 2 3 4 1 2 3 1 2 1 2 3 4 5 1 2 3 4 5 1 1 1 2 3 1 2 --sundar |
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