| To: | "Lambert.Winnie" <lambert.winnie@ensco.com> |
|---|---|
| Subject: | Re: linear interpolation through missing data |
| From: | Sundar Dorai-Raj <sundar.dorai-raj@PDF.COM> |
| Date: | Tue, 24 Aug 2004 17:13:44 -0700 |
| Cc: | S-PLUS Newsgroup <s-news@lists.biostat.wustl.edu> |
| In-reply-to: | <8986151694190742869D08450EE4DCDE4508D9@amu-exch.ensco.win> |
| Organization: | PDF Solutions, Inc. |
| References: | <8986151694190742869D08450EE4DCDE4508D9@amu-exch.ensco.win> |
| Reply-to: | sundar.dorai-raj@PDF.COM |
| User-agent: | Mozilla/5.0 (Windows; U; Windows NT 5.0; en-US; rv:1.4) Gecko/20030624 Netscape/7.1 (ax) |
Lambert.Winnie wrote: S-PLUS6 on Windows XPI found this question in 3 emails in the archive, but did not see an answer. I have looked in my S-PLUS books, but perhaps am looking in the wrong place for the wrong thing. I want to do a relatively simple linear interpolation across missing values in a vector, e.g. ...850 862 875 NA NA 927 946... weighted by another non-missing (and never missing!) variable. Is there a function for this? If not, I can trudge through and figure out an algorithm, but would rather not waste time if I can do it in a one-liner. Thanks much. Try ?approx. You'll need to supply an `x' but here's an example to help: set.seed(1) n <- 100 y <- sort(rnorm(n)) x <- seq(n) na <- sample(n, 3) # remove 3 points guess <- approx(x[-na], y[-na], xout = x[na])$y cbind(true = y[na], guess) --sundar |
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