| To: | <s-news@lists.biostat.wustl.edu> |
|---|---|
| Subject: | Repeated-measures Designs |
| From: | <Jody.Biggs@csiro.au> |
| Date: | Wed, 1 Sep 2004 11:49:57 +1000 |
| Thread-index: | AcSPF82lvpYAZ9M+TSKkCuAFCM3jjw== |
| Thread-topic: | Repeated-measures Designs |
|
G'Day S+
Users,
I am currently try
to use a split-plot type ANOVA to analysis an unusual experimental design based
on the examples given in the SPlus statistics Vol1 - Repeated Measures
Design.
The experiment
consists of a total of 42 subjects (ID) split between two
treatments.
A maximum of 27
repeated measurement for each subject were taken.
Some subjects
were removed from the experiment progressively through time. i.e. 3 per
treatment per day so by the end of the experiment there remained only 3 subjects
per treatment.
The results for the
split-plot ANOVA are below.
What I would like to
know is where it gets the 7 degrees of freedom for time factor
(Hours)?
I realise that this
term doesn't appear when there are equal number of measurements as per the
repeated-measures design example in SPlus Statistics Vol1.
Also if anyone can
suggest an alternative analysis I would be interested.
Thanks in
advance
Jody
> summary(aov(LN.N2N
~ Treatment*Hours + Error(ID), data = "" weights = No.obs,))
Note: This analysis was done with weights The results below are on the weighted scale Error: ID Df Sum of Sq Mean Sq F Value Pr(F) Treatment 1 141.1602 141.1602 8.102543 0.00834138 Hours 7 593.3629 84.7661 4.865543 0.00119483 Treatment:Hours 6 286.9992 47.8332 2.745607 0.03251294 Residuals 27 470.3865 17.4217 Error:
Within
Df Sum of Sq Mean Sq F Value Pr(F) Hours 26 4438.693 170.7190 24.98999 0.000000 Treatment:Hours 26 223.098 8.5807 1.25605 0.180978 Residuals 480 3279.117 6.8315 |
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