List question

[Dave Evens <devens8765@yahoo.com>]

Dear all,

My query involves a list. For example, suppose I have
a list x

x <- list(list(rpois(100,2), list(LETTERS[1:20]),
list()),
          list(rpois(150,2), list(LETTERS[1:12]),
list()),
          list(rpois(200,2), list(LETTERS[1:19]),
list()))


and I want to replace the empty list in each sub-list
of x, this is easy using the for-loop

for(k in 1:length(x)) x[[k]][[3]] <- matrix(rnorm(100,
10, 2), 10,10)

but how do I the equivalent of this using the lapply
command?

This is the syntax of the lapply command

lapply(1:length(x), function(k) matrix(rnorm(100, 10,
2), 10,10))

but how do I get it in x[[k]][[3]]?

I've tried  using the assign command but it doesn't
appear to work.

Thanks for any help in advance.

Dave







                
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