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How calculation degrees of freedom

To: s-news@lists.biostat.wustl.edu
Subject: How calculation degrees of freedom
From: gabriela escati peñaloza <gescati@yahoo.com.ar>
Date: Mon, 30 Jan 2006 14:54:18 +0000 (GMT)
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Hi,
I' m having a hard time understanding the computation of degrees freedom when runing nlme() on the following model:
 
> formula(my data.gd)
dLt ~ Lt | ID
TasavB<- function(Lt, Linf, K) (K*(Linf-Lt))
 
my model.nlme <- nlme (dLt ~ TasavB(Lt, Linf, K),
data = "" data.gd,
fixed = list(Linf ~ 1, K ~ 1),
start = list(fixed = c(70, 0.4)),
na.action= "" naPattern = ~!is.na(dLt))
 
> summary(my model.nlme)
Nonlinear mixed-effects model fit by maximum likelihood
  Model: dLt ~ TasavB(Lt, Linf, K)
 Data: my data.gd
       AIC      BIC    logLik
  13015.63 13051.57 -6501.814
Random effects:
 Formula: list(Linf ~ 1 , K ~ 1 )
 Level: ID
 Structure: General positive-definite
            StdDev   Corr
    Linf 7.3625291 Linf 
       K 0.0845886 -0.656
Residual 1.6967358      
Fixed effects: list(Linf + K ~ 1)
        Value Std.Error   DF  t-value p-value
Linf 69.32748 0.4187314  402 165.5655  <.0001
 & nbsp; K  0.31424 0.0047690 2549  65.8917  <.0001
Standardized Within-Group Residuals:
      Min         Q1         Med        Q3      Max
 -3.98674 -0.5338083 -0.02783649 0.5261591 4.750609
Number of Observations: 2952
Number of Groups: 403
 
Why are the DF of Linf and K different? I would apreciate if you could point me to a reference.
I working with Splus 6.1 for Windows


Lic. Gabriela Escati Peñaloza
Biología y Manejo de Recursos Acuáticos
Centro Nacional Patagónico(CENPAT).
CONICET
Bvd. Brown s/nº.
(U9120ACV)Pto. Madryn
Chubut
Argentina

Tel: 54-2965/451301/451024/451375/45401 (Int:277)
Fax: 54-29657451543

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