|
Rich (and others),
Sort of. This is more
what I want.
x<-1
for (i in seq(1,10,length=30)){
x<-append(x,
sort(rnorm(30, 50, i)))
}
The problem is that the only way I can figure
out how to do it is by first starting with "x" having some value in it so that I
can use the "append" statement. I then have to delete the first "row"
before using the data. I decided to use the "for" statement because I also
have a command that does the following to apply a "grouping variable" for each
set of random numbers:
y<-1
for (i in 1:30){
y<-append(y, rep(i,
30))
}
I have the same problem here, though.
Any ideas?
Thanks,
Kyle
From: Richard Pugh
[mailto:rpugh@mango-solutions.com]
Sent: Sat 4/22/2006 5:32
AM
To: Roberts, J. Kyle
Subject: RE: [S] random
samples
Hi
Kyle
Is this what you
want?
> sapply(seq(1,
10, length=30), rnorm, n=1, mean=0)
[1]
-0.81725561 -3.08122241 1.06784505
-0.08974292 1.67823407 -4.70454218
[7]
0.30273341 0.99100837 -4.92922917
-1.96928729 0.76185292 10.73067244
[13]
3.09920886 1.87420172 -0.78714101 9.79541771
-3.35487967 2.44693247
[19]
10.70601907 1.68186712 5.70838928
8.46980920 -0.97129270 -6.99468471
[25]
-13.38216398 0.12119373 -3.14704500
0.45912028 -0.43485937 -5.46393800
Rich.
From:
s-news-owner@lists.biostat.wustl.edu
[mailto:s-news-owner@lists.biostat.wustl.edu] On Behalf Of Roberts, J. Kyle
Sent: 21 April 2006 21:50
To:
s-news@lists.biostat.wustl.edu
Subject: [S] random
samples
I want to create 30 random samples
of 30 scores all in the same vector (all with the same mean). The twist is
that I want to be able to specify a different SD for each sample such that
seq(1, 10, length=30). Before I put the random samples together, however,
I want them to appear in ascending order (within each group). I can easily
do this the long way, but I wonder if someone can figure out an easy
way.
|