Re: plot histogram of a distribution

[David L Lorenz <lorenz@usgs.gov>]

Raghu,
  If you look at the formula in
your for loop, you will see that it has exactly the same appearance as
the one that works. That means the routines that evaluate the formula see
the same thing and are looking at a column named f.name in the data set
and not a column named FCF. You know that f.name is a variable that represents
that column, but the routine that evaluates the formula does not.
  For cases like this, you can
use the as.formula() function. Try this:

histogram(as.formula(paste("~",
f.name, "| Country")), data=""
= 10,type="count")

  I do not see where Country comes
from if you select only the column f.name from data!
Dave

"Krishnamachari, Raghuraman" <Raghu.Krishnamachari@leggmasonasia.com.sg>
Sent by: s-news-owner@lists.biostat.wustl.edu

08/23/2006 09:52 PM

To	<s-news@lists.biostat.wustl.edu>
cc
Subject	[S] plot histogram of a distribution

Dear all,
 
I am new to this list and splus. I am trying
to plot a histogram of a distribution using "histogram".
The issue is i am unable to call this in
a loop with different Factors variables.
 
> factor.names
[1] "Tobin.Q" "EBITDA"  "FCF" 
 
> factor.cols
[1] "Tobin.Q" "EBITDA"  "FCF"  
 
=================================
for(i in 1:length(factor.cols)) {
 
 f.name<-factor.names[i]
histogram(~ f.name | Country, data=""
= 10,type="count")
}
====================================
 
when i replace f.name with the numeric column
names like FCF,EBITDA individually, the above function works. But how to
pass these values in a loop.
 
histogram(~ FCF | Country, data=""
= 10,type="count") -- works 
 
whereas
 
histogram(~ "FCF" | Country, data=""
= 10,type="count")
-- gives different results.
 
 
Hope someone throw light on this.
 
thanks,
 
Raghu.



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