Thanks JAK!
Awesome.....
-Sohail
-----Original Message-----
From: John Kershaw [mailto:kershaw@unb.ca]
Sent: Monday, April 02, 2007 6:03 PM
To: Khan, Sohail
Cc: s-news@lists.biostat.wustl.edu
Subject: Re: [S] calculating the z scores by apply function
Sohail,
This is relatively straightforward, apply outputs the results of the first
row as a column vector, then cbind() subsequent rows. If you use
t(apply()) you should get the matrix you want:
temp<-matrix(c(rep(1,3),rep(2,3),rep(3,3)),nrow=3,byrow=T)
> temp
[,1] [,2] [,3]
[1,] 1 1 1
[2,] 2 2 2
[3,] 3 3 3
> apply(temp,1,cumsum)
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 2 4 6
[3,] 3 6 9
> t(apply(temp,1,cumsum))
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 2 4 6
[3,] 3 6 9
for example.
Hope that helps.
JAK
On Mon, 2 Apr 2007, Khan, Sohail wrote:
> Dear all,
>
> I have a large data.frame as follows:
> x1 x2 x3 x4 x5
> 2.56 3.02 4.00 3.87 5.25
> 1.25 2.20 1.75 2.32 2.14
> 6.02 5.98 4.99 5.32 5.66
>
> I would like to calculate the z scores for each row. I am using the package
> "outliers" which has a function for z cores. I am using this function in
> apply(). However, the out put is not a matrix with the same dim() as the
> original input data. For example, my data frame is 54675 X 15....and the
> output is reversed 15 X 54675. I cant figure this out. I would appreciate
> your expert advice. Thanks.
>
> Sohail Khan
> Scientific Programmer
> COLD SPRING HARBOR LABORATORY
> Genome Research Center
> 500 Sunnyside Boulevard
> Woodbury, NY 11797
> (516)422-4076
>
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